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If a program successfully calls the ALLOC function twice, it will often own two adjacent memory blocks. If it then calls DEALLOC on each block, there will be two adjacent free memory blocks. When allocating memory again, these free blocks somehow need to be coalesced so that the free memory wouldn’t become endlessly fragmented.，这一点在一键获取谷歌浏览器下载中也有详细论述
cancel-safe in this expanded sense. That's how we produced the deadlock above，推荐阅读下载安装汽水音乐获取更多信息
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